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59\A3R:\F3\CE"\B6\80\88\00\00i1u4ê\E9\F2á\A6\A2\FACM\93WMb*\E0*\00\00\00\00\00(\A8\80\00\00\80\00\00\00\00\00\00\00\00\00\FF\D9<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>C///</title>
</head>
from __future__ import annotations

import re
from typing import Iterable

from ._loop import loop_last
from .cells import cell_len, chop_cells

re_word = re.compile(r"\s*\S+\s*")


def words(text: str) -> Iterable[tuple[int, int, str]]:
    """Yields each word from the text as a tuple
    containing (start_index, end_index, word). A "word" in this context may
    include the actual word and any whitespace to the right.
    """
    position = 0
    word_match = re_word.match(text, position)
    while word_match is not None:
        start, end = word_match.span()
        word = word_match.group(0)
        yield start, end, word
        word_match = re_word.match(text, end)


def divide_line(text: str, width: int, fold: bool = True) -> list[int]:
    """Given a string of text, and a width (measured in cells), return a list
    of cell offsets which the string should be split at in order for it to fit
    within the given width.

    Args:
        text: The text to examine.
        width: The available cell width.
        fold: If True, words longer than `width` will be folded onto a new line.

    Returns:
        A list of indices to break the line at.
    """
    break_positions: list[int] = []  # offsets to insert the breaks at
    append = break_positions.append
    cell_offset = 0
    _cell_len = cell_len

    for start, _end, word in words(text):
        word_length = _cell_len(word.rstrip())
        remaining_space = width - cell_offset
        word_fits_remaining_space = remaining_space >= word_length

        if word_fits_remaining_space:
            # Simplest case - the word fits within the remaining width fo